If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(7+2x)^2=11
We move all terms to the left:
(7+2x)^2-(11)=0
We add all the numbers together, and all the variables
(2x+7)^2-11=0
We move all terms containing x to the left, all other terms to the right
(2x+7)^2=11
| 12=w12 | | t=-16t2+48t+4 | | 6v+15=2v+47 | | 3x+-1(x+-7)=18 | | x+10=-5x-4 | | 16^2+x^2=27^2 | | 22.5+2y=7y+11 | | F(4)=6x-10 | | 6p+3p-5=112 | | 5w+1=6w+5 | | ∠1=(6x+5)°,∠2=(11x+12) | | x²-27x=0 | | 4e=58e= | | 4x+4+30=90 | | 7c7=4c+17 | | 7=(0.7)x | | (n+5)=-16 | | Y=2*4x | | 8x-4-6x+12=0 | | n/4-5/3=n/12 | | 115-u=182 | | 4.5+1.75x=20 | | x-11/5=51/2 | | 10x–38=4x-2 | | X/7/x=28/16 | | -3x-8=3x+10 | | 7x+5x-6x=99 | | 5x+27=360 | | 0.9^x=0.22 | | 29.338+2918x=4526 | | H=-16t^2+80t+200 | | -2-1+3=5x+7x+47x |